Password count duplicate and sort.

JohnTerry · 07-09-2018, 09:31 AM

New member and love python xD

Code:
from collections import defaultdict
from tqdm import tqdm

class Counter():
    def __init__(self, input_file):
        self.mp_dict = defaultdict(int)
        self.input_file = input_file
        self.sorted_dict = None

    def run(self):
        print('Sorting')
        with open(self.input_file, 'r+') as f:
            for line in tqdm(f.readlines()):
                if len(line) > 1:
                    if line.strip() in self.mp_dict:
                        self.mp_dict[line.strip()] += 1
                    elif line.strip() not in self.mp_dict:
                        self.mp_dict[line.strip()] = 1
        self.sorted_dict = sorted(self.mp_dict.items(), key=lambda x: x[1], reverse=True)
        self.write_result()

    def write_result(self):
        print('Writing result')
        with open(self.input_file + '_result.txt', 'a+') as r:
            for item in tqdm(self.sorted_dict):
                r.write(item[0] + '\n')


p = Counter(r'/home/username/password.txt').run()
print('Done!!!')