Star pattern in Shell - Printable Version

Star pattern in Shell - Printable Version

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+--- Forum: Coding (https://sinister.li/Forum-Coding--71)
+--- Thread: Star pattern in Shell (/Thread-Star-pattern-in-Shell)

Star pattern in Shell - alok9shm - 09-08-2014

I'm learning Shell programming now, and got a homework that wants me to display this :

Quote:*
**
***
****
*****

Now, I tried it using the while loop, as I am still due to learn the for loop syntax in shell.

Here's my code:

PHP Code:
echo "enter size of star"
read n
i=1
j=1
while [ $i -le $n ]
do
while [ $j -le $i ]
do
echo "*"
j=`expr $j + 1`
done
echo -n " "
i=`expr $i + 1`
done 

The result is this:

Quote:*
*
*
*
*

What I have in mind: echo "*" prints * in a new line normally
and echo -n "*" prints * in the same line without going for a new line.
The new line thing is still not clear to me, so Correct me if i'm wrong.

In C or C++ "\n" did the trick for me.

Star pattern in Shell - alok9shm - 09-08-2014

I'm learning Shell programming now, and got a homework that wants me to display this :

Quote:*
**
***
****
*****

Now, I tried it using the while loop, as I am still due to learn the for loop syntax in shell.

Here's my code:

PHP Code:
echo "enter size of star"
read n
i=1
j=1
while [ $i -le $n ]
do
while [ $j -le $i ]
do
echo "*"
j=`expr $j + 1`
done
echo -n " "
i=`expr $i + 1`
done 

The result is this:

Quote:*
*
*
*
*

RE: Star pattern in Shell - Psycho_Coder - 09-08-2014

Code:
echo "enter size of star"
read n
i=1
j=1
while [ $i -le $n ]
do
	while [ $j -le $i ]
	do
		echo -n "*"
		j=`expr $j + 1`
	done
echo " "
i=`expr $i + 1`
j=1
done

try this

RE: Star pattern in Shell - Psycho_Coder - 09-08-2014

Code:
echo "enter size of star"
read n
i=1
j=1
while [ $i -le $n ]
do
	while [ $j -le $i ]
	do
		echo -n "*"
		j=`expr $j + 1`
	done
echo " "
i=`expr $i + 1`
j=1
done

try this

RE: Star pattern in Shell - alok9shm - 09-09-2014

(09-08-2014, 09:49 AM)Psycho_Coder Wrote:
Code:
echo "enter size of star" read n i=1 j=1 while [ $i -le $n ] do while [ $j -le $i ] do echo -n "*" j=`expr $j + 1` done echo " " i=`expr $i + 1` j=1 done

try this

Thanks a lot. It works.

I got the mistake. my while loop structure was incorrect/misplaced. Then i used -n in the wrong place. Thanks.

RE: Star pattern in Shell - Psycho_Coder - 09-09-2014

ok.

Solved and Closed