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Can someone help me - Printable Version +- Sinisterly (https://sinister.li) +-- Forum: General (https://sinister.li/Forum-General) +--- Forum: The Lounge (https://sinister.li/Forum-The-Lounge) +--- Thread: Can someone help me (/Thread-Can-someone-help-me--27463) |
Can someone help me - shizelkid - 04-15-2014 I need someone to help me with my homework 30+11= 5+3= 15-4= 8-4= 31+10= 1*1= 5+6= 5-3= 15+15+2= 15+16= . 15+6= 100-29= 50+1= 8+0= 9*9+10= 0+9= 22/2= 9*9= 0+1= 6*2= 6*7= 1+0= 9*9= 6*10+2= 120/2+2= 11*2-1= 8*0+8= 0+4= 4*10+1= 25*2+2= 4+4= 2.5+2.5= I hope you can help me. Answers Code: Vas
va svasvasv as vasva sva sva svasvas va
Hi Sinister.ly thank you for helping me.
Ni Kdnaktwm.lq ohsik rju xjr zzlhdny he.
19 14111221.11 18191 112 211 2218412 85.
4 1 4 1033.27 5 9 1 801 408 662 45
== ========.== ===== === === ======= ==
40 10401033.27 50901 801 408 6620045 00
18 14111221.11 18191 112 211 2218412 85What i need help with is i want to make a program that'll do all this for me. will convert it to math and then out of math. RE: Can someone help me - potatoman - 04-15-2014 Maybe you can simply use a calculator RE: Can someone help me - Reiko - 04-15-2014 Remove the = signs and then paste it into a Python interpreter. RE: Can someone help me - shizelkid - 04-16-2014 nvm, its not math homework. its cryptography. I uses a phrase and then i changed the letters around using a code and then i changed the letters to numbers then fliped the numbers and then made math equations. this way you have to solve the math then change the answer like 80 is really 08 or 8 or as in H the 8 letter of the alphabet. Then change the H to the right letter from the code. Get it now? I want to make a pc program that will save me the work of doing it all by hand and make it easier. if it cant be done thats fine. RE: Can someone help me - Equinox - 04-16-2014 Try this: Code: import base64,string
z2 = input('Cryptographic phrase: ')
if z2[0] in string.ascii_letters:
msg = b'a3JvdyBsb29oY3Mgbm8gdGFlaGMgdCdub0Q='
x3 = base64.b64decode(msg)
print(x3.decode('ascii')[::-1])
else: print('''That's no phrase! >:(''')^ Python 3 RE: Can someone help me - shizelkid - 04-16-2014 okay, Thank you Duubz. Ill try it out tmro. |