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Python Challenge - Printable Version

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+--- Thread: Python Challenge (/Thread-Python-Challenge)

Pages: 1 2


RE: Python Challenge - Nil - 12-12-2015

(12-12-2015, 01:22 PM)Megan Wrote:
Code:
#!/usr/bin/env python diamond = [" *"," ***"," *****","*******"," *****"," ***"," *"] var = 0 while var == 0: while var < 7: print diamond[var] var += 1

Whilst technically the first loop does absolutely nothing, it does actually count as a loop and so the second loop counts as the nested loop so yeah, 8 lines long, would love more challenges like this!

For gosh sake, use Python 3+! Wink2
I'll let this one pass because I like it, but... technically wouldn't this be printing multiple asterisks each iteration breaking one of the rules? What do you think?


RE: Python Challenge - Megan - 12-12-2015

(12-12-2015, 07:59 PM)God Wrote: For gosh sake, use Python 3+! Wink2
I'll let this one pass because I like it, but... technically wouldn't this be printing multiple asterisks each iteration breaking one of the rules? What do you think?

Well technically it's printing them in a loop, yeah it does break the rule you specified about single printing.

So I will re-do the challenge and make it print singularly.

Code:
#!/usr/bin/env python symbol = "*" var = 1 rnd = 0 tim = 0 while var == 1: while tim < 9: if var == 1 and rnd == 0: print " " + symbol var += 2 tim += 1 elif var == 3 and rnd == 0: print " " + symbol * var var += 2 tim += 1 elif var == 5 and rnd == 0: print " " + symbol * var var += 2 tim += 1 elif var == 7 and rnd == 0: print symbol * var rnd = 1 tim += 1 elif var == 7 and rnd == 1: var -= 2 tim += 1 print " " + symbol * var elif var == 5 and rnd == 1: var -= 2 tim += 1 print " " + symbol * var elif var == 3 and rnd == 1: var -= 2 tim += 1 print " " + symbol * var exit()

There we go @GOD I managed to adhere to the only printing it once rule.


RE: Python Challenge - Nil - 12-12-2015

(12-12-2015, 08:03 PM)Megan Wrote: Well technically it's printing them in a loop, yeah it does break the rule you specified about single printing.

So I will re-do the challenge and make it print singularly.

Code:
#!/usr/bin/env python symbol = "*" var = 1 rnd = 0 tim = 0 while var == 1: while tim < 9: if var == 1 and rnd == 0: print " " + symbol var += 2 tim += 1 elif var == 3 and rnd == 0: print " " + symbol * var var += 2 tim += 1 elif var == 5 and rnd == 0: print " " + symbol * var var += 2 tim += 1 elif var == 7 and rnd == 0: print symbol * var rnd = 1 tim += 1 elif var == 7 and rnd == 1: var -= 2 tim += 1 print " " + symbol * var elif var == 5 and rnd == 1: var -= 2 tim += 1 print " " + symbol * var elif var == 3 and rnd == 1: var -= 2 tim += 1 print " " + symbol * var exit()

There we go @GOD I managed to adhere to the only printing it once rule.
Nice! What is the point of exit()? Is that just if you're running through the interpreter?


RE: Python Challenge - Megan - 12-12-2015

(12-12-2015, 08:49 PM)God Wrote: Nice! What is the point of exit()? Is that just if you're running through the interpreter?

the loop doesn't break properly and I cba to fix it when I'm this tired so it's a dirty way to end the python script.


RE: Python Challenge - Nil - 12-12-2015

(12-12-2015, 08:52 PM)Megan Wrote: the loop doesn't break properly and I cba to fix it when I'm this tired so it's a dirty way to end the python script.

Oh okay. It actually bothered me because when I run the script it automatically brings up a prompt asking me to kill the program, and clicking yes ends the shell.


RE: Python Challenge - Megan - 12-12-2015

(12-12-2015, 08:55 PM)God Wrote: Oh okay. It actually bothered me because when I run the script it automatically brings up a prompt asking me to kill the program, and clicking yes ends the shell.

haha yeah, I just use linux terminals so it exits for me.