[Sapientia]

This is a mathematical way to count how many characters there are in a given input which is an integer.

Code:

Function intCount(ByVal input As Integer) Dim count As Integer = 1 Dim power As Integer = 10 While power <= input count += 1 power *= 10 End While Return count End Function Sub Main() Console.WriteLine(intCount(Console.ReadLine)) Console.ReadLine() End Sub

What this is doing is incrementing the starting counter of 1 each time by 1 that the power is able to be multiplied by 10, but still be lower than the input of the function.

[Customer]

HOLY SHIT YOU'RE BACK!

Welcome back!

Totally off topic but sorry.

[Sapientia]

Haha, no problem man. Hit me up on Skype @Sapientia.coder if you want.

[0xDEAD10CC]

This is a mathematical way to count how many characters there are in a given input which is an integer.

Code:

Function intCount(ByVal input As Integer) Dim count As Integer = 1 Dim power As Integer = 10 While power <= input count += 1 power *= 10 End While Return count End Function Sub Main() Console.WriteLine(intCount(Console.ReadLine)) Console.ReadLine() End Sub

What this is doing is incrementing the starting counter of 1 each time by 1 that the power is able to be multiplied by 10, but still be lower than the input of the function.

There are no "characters" in an integer... :\ You mean digits?

Additionally you can use logarithms for this instead.

Code:

floor(log10(abs(x))) + 1

Here's my C macro as a proof of concept:

Code:

#define digits(x) (floor(log10(abs(x))) + 1)

Code:

#include <iostream> #include <cmath> #define digits(x) (floor(log10(abs(x))) + 1) int main() { std::cout << digits(23480) << '\n'; // 5 }

[Sapientia]

There are no "characters" in an integer... :\ You mean digits?

Additionally you can use logarithms for this instead.

Code:

floor(log10(abs(x))) + 1

Here's my C macro as a proof of concept:

Code:

#define digits(x) (floor(log10(abs(x))) + 1)

Code:

#include <iostream> #include <cmath> #define digits(x) (floor(log10(abs(x))) + 1) int main() { std::cout << digits(23480) << '\n'; // 5 }

Yeah, didn't mean to say character.

[abosauf]

Hello

I am a new Edu

You can helper work a new topic

I worked the subject and I want to transfer to the Department of vb.net

https://www.sinister.ly/usercp.php?action=drafts