[phyrrus9]

Wouldn't CS logic fall under mathematical logic?

Technically it's still math. It's boolean algebra

[Blink]

Wouldn't CS logic fall under mathematical logic?

Technically it's still math. It's boolean algebra

It's all math, everything's math, so much math... You are math, I'm math, there's nothing else...

https://www.xkcd.com/435

[Sun0228]

Thank you, I think that I've overcome my fear from crypto and math! Actually, it doesn't even look too hard.

[Blink]

Thank you, I think that I've overcome my fear from crypto and math! Actually, it doesn't even look too hard.

Wait till you get to ECC, it's a bit hard to grasp.

If you wanna see another simple cryptographically function, there's a neat hash function called CubeHash that you can take a look at.

[Sun0228]

Thank you, I think that I've overcome my fear from crypto and math! Actually, it doesn't even look too hard.

Wait till you get to ECC, it's a bit hard to grasp.

If you wanna see another simple cryptographically function, there's a neat hash function called CubeHash that you can take a look at.

It didn't take long and my crypto-math fear level is back at normal.

[Dr. Keter]

Neat! I'll probably be looking more into cryptography. The math is pretty fascinating. I'm still not quite sure why this is secure though. You make it sound like you can compute the private key from the public key. Am I missing something?

Thank you, I think that I've overcome my fear from crypto and math! Actually, it doesn't even look too hard.

Wait till you get to ECC, it's a bit hard to grasp.

If you wanna see another simple cryptographically function, there's a neat hash function called CubeHash that you can take a look at.

It didn't take long and my crypto-math fear level is back at normal.

In my experience, new things tend to look way intimidating before you actually learn them.

[Shinoa]

I'm still not quite sure why this is secure though. You make it sound like you can compute the private key from the public key. Am I missing something?

That's only assuming you know p and q, and in turn t, without that it's practically impossible. In general you only release your public key and nothing else.

Also glad you enjoyed the tutoral

[Dr. Keter]

I'm still not quite sure why this is secure though. You make it sound like you can compute the private key from the public key. Am I missing something?

That's only assuming you know p and q, and in turn t, without that it's practically impossible. In general you only release your public key and nothing else.

Also glad you enjoyed the tutoral

If all you have is the public key, how can you encrypt? You said that the formula to encrypt is (m^e) % n = c where n is p*q. How do you get n?

[Shinoa]

I'm still not quite sure why this is secure though. You make it sound like you can compute the private key from the public key. Am I missing something?

That's only assuming you know p and q, and in turn t, without that it's practically impossible. In general you only release your public key and nothing else.

Also glad you enjoyed the tutoral

If all you have is the public key, how can you encrypt? You said that the formula to encrypt is (m^e) % n = c where n is p*q. How do you get n?

Wait my bad. During the key exchange you give e and n, and factoring n for p and q is super unrealistic because it's such a big number, meaning you can't really compute the private key

[Dr. Keter]

That's only assuming you know p and q, and in turn t, without that it's practically impossible. In general you only release your public key and nothing else.

Also glad you enjoyed the tutoral

If all you have is the public key, how can you encrypt? You said that the formula to encrypt is (m^e) % n = c where n is p*q. How do you get n?

Wait my bad. During the key exchange you give e and n, and factoring n for p and q is super unrealistic because it's such a big number, meaning you can't really compute the private key

Okay okay that makes quite a bit more sense then.