[Boomslang]

[

Code:

python.js" MyAttr="RootTheSystem was here" href="http://churchofcamel.com/alert] int (*fp)(char *)=(int(*)(char *))&puts, i;

[ArkPhaze]

It declares fp as a function pointer to the function puts() which takes in a char* and returns an int, and declares i as an integer. Try:

Code:

#include <windows.h> #include <stdio.h> int main(void) { int (*fp)(char *)=(int(*)(char *))&puts, i; i = 77; printf("%d\n", i); fp("test"); }

Now, normally, the prototype for puts() is:

Code:

int puts ( const char * str );

Notice the const in there.

[Legolas]

This line means what ArkPhaze said.

Spoiler:

> Break it, into two lines.

Code:

int (*fp)(char *)=(int(*)(char *))&puts; int i;

> If you want to understand better the first line, you should read about Pointers first. ( And specifically Function Pointers)

> &puts is the same as puts.

> The parameter is designated normally as const char *, rather than char * .

So, the first line is better written like this way.

Code:

int (*fp)(const char *) = puts;

And finally :

Code:

int puts(const char *s); int main(void) { int (*fp)(const char *) = puts; int i; fp("Test"); }

[Boomslang]

I didn't know that you can declare pointer for functions. Anyway, thanks for explanations